In figure , AB = AC and BE = DC ,prove that ∠BAE = ∠CAD
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hhwhyyh
Step-by-step explanation:
In figure , AB = AC and BE = DC ,prove that ∠BAE = ∠CAD
Answered by
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Answer:
NEXT TIME ONWARD PLZ MEANTION THE FIGURE AS WELL .Well since u haven't mentioned the fig i assumed it to be a triangle
Step-by-step explanation:
n △ADB and △ADC, we have
AB=AC (given)
BD=DC (given)
AD=AD (common)
∴ △ADB≅△ADC [By SSS congruence property]
(i) ∠ADB=∠ADC (corresponding parts of the congruent triangles ) ...(1)
Now, ∠ADB+∠ADC=180° [∵∠ADB and ∠ADC are on the straight line]
⇒∠ADB+∠ADB=180 ° [from(1)]
⇒2∠ADB=180 °
⇒2∠ADB= 180°/2 =90 °
∴∠ADB=∠ADC=90 °[from (1)]
(ii) ∠BAD=∠CAD (∵ corresponding parts of the congruent triangles)
I hope it help you...
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