Question

in figure AB=AC and D is the mid point of BC state the 3 pairs of equal parts in
Triangle ADB and triangle ADC
is ADB= ADC? give reason
is <B = <C? why?
PLEASE ANSWERRR ASAP​

Answer 1

Answer:

Here in \Delta ADB and \Delta ADC.

i) Three pair of equal parts are:

AD = AD ( common side )

BD = CD ( as d is the mid point of BC)

AB = AC (given in the question)

ii) Now,

by SSS Congruency rule,

\Delta ADB\cong \Delta ADC

iii) As both triangles are congruent to each other we can compare them and say

\angle B = \angle C.

Answer 2

Step-by-step explanation:

a) AB=AC (given)

BD=DC (D is the midpoint of BC)

AD=AD (common)

b) ADB is conguruent to ADC (By SSS conguruence rule)

c) BAD=CAD

yes, it is equal (By ACP)