in figure ab and ac are the tangent ab is equal to 6 cm and angle A = 60 degree then the perimeter of triangle ABC is
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Two same tangent drawn from a external point is same.
so ab=ac=6cm
now as angle a = 60 degree
so angle b=angle c =60 degree (base angle of isosceles triangle=60 degree)
so abc is equilateral.
so perimeter of triangle abc =6+6+6=18 cm
so ab=ac=6cm
now as angle a = 60 degree
so angle b=angle c =60 degree (base angle of isosceles triangle=60 degree)
so abc is equilateral.
so perimeter of triangle abc =6+6+6=18 cm
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