in figure AB and BC are two chords equidistant from O prove that BO bisects angle ABC
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Given: In the figure AB = CB and O is the centre of the circle. To Prove: BO bisects ∠ABC. Construction: Join OA and OC.Proof : In ∆OAB and ∆OCB OA = OC [Radii of the same circle] AB = CB [Given] OB = OB [Common] ∴ ∆OAB ≅ ∆OCB [By SSS] ∴ ∠ABO = ∠CBO [By cpctc] ⇒ BO bisects ∠ABC
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