In figure AB and CD are parallel AB =5cm and AC=
a) the area of triangle ABC?
b)area of triangle ABD?why
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Answer:
In right angles triangle BAC, AB=5cm and AC=12cm
Area of triangle=
2
1
×base×height=
2
1
×AB×AC
=
2
1
×5×12=30cm
2
Now, in ΔABC,
Area of triangle ABC=
2
1
×BC×AD
⇒30=
2
1
×13×AD
⇒ AD=
13
30×2
=
13
60
cm.
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