Question

in figure AB and CD are two parallel tangents to a circle with centre o ST is tangent segment between the two parallel tangents touching the circle Q show that <SOT=90°

Answer 1

Answer:

<SOT=90°

Step-by-step explanation:

From the figure we get,

AB⊥ST then <ASQ = 90° and CD⊥TS then <ATQ = 90°

<ASO = <QSO = 90/2 = 45°

Similarly, <OFQ = 45°

To find <SOT

Consider ΔSOT,

<OFS = 45° and <OSF = 45°

<SOT + <OFS + OSF = 180°    (angle sum property)

<SOT  = 180°  - ( <OFS + OSF) = 180°  - (45°  +45° ) = 180°  - 90°  = 90°

Therefore <SOT = 90°

Answer 2

Answer:

SAME!SMJNSKEE

EUEHE282882