In figure,AB,CD and EF are three parallel lines, if 4y=5x and z= y- 30, find angle q.
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Given 4y = 5x→ 1 and z = y - 30→ 2 As CD∥ AB y = 180 - x Substituting in 1 4(180 - x) = 5x 4 × 180 = 9x x = 80° So, y = 100° but z = y - 30° ...
Given 4y = 5x→ 1 and z = y - 30→ 2 As CD∥ AB y = 180 - x Substituting in 1 4(180 - x) = 5x 4 × 180 = 9x x = 80° So, y = 100° but z = y - 30° ...
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