in figure AB || CD
find angle PCD and angle CPD
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AB||CD therefore angle APQ is 50
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∠CPD + ∠APC = 180 (LINEAR PAIR)
∠CPD = 180 - 122
∠CPD = 58
By alternate angles property,
∠BAD = ∠PDC = 50
In triangle CPD,
∠PCD + ∠CPD + ∠PDC = 180 (ANGLE SUM PROPERTY OF TRIANGLES)
∠PCD = 180 - 108
∠PCD = 72
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