Question

in figure, AB║CD find x

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

Let us draw a line EF parallel to the lines AB and CD.

Then ∠BPF=∠ABP=48

o

[ alternate angle].......(1).

Also, ∠CPF=∠PCD=24

o

[ alternate angle]......(2).

Now

∠BPC=∠BPF+∠CPF=48

o

+24

o

=72

o

.

Then x=360

o

−72

o

=288

o

.