Question

In figure, AB || CD, then find the value of a + b + c - d.
A+B+C-D​

Answer 1

Answer:

Hey! Here is your answer!

Step-by-step explanation:

Given that AB∣∣CD

Taking BC as transversal,

∠ABC=∠BCD (alternate interior angles)

3x=105

∘

x=35

∘

Also, given that BC∣∣DE.

Taking CD as transversal,

∠CDE=∠BCD=105

∘

(alternate interior angles)

Now applying angle sum property in triangle CDE,

∠CDE+∠DEC+∠DCE=180

∘

105

∘

+y+24

∘

=180

∘

y=51

∘

solution