Question

in figure AB I BE and EF 1 BE. If BC = DE and AB = EF, then A AB
congruent to which triangle
​

Answer 1

Correct Question : In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to ?

Answer:

In ∆ABD and In ∆FEC

→ AB = EF .......[Given]

→ ∠FEC = ∠ABD .......[ Each 90°]

→ BC = DE .......[Given and CD is common in both ∆]

→ BC + CD = CD + DE

→ BD = CE

⛬ ΔABD ≅ ΔFEC ......[By SAS rule]