in figure ab is a chord of length 16 CM of a circle of radius 10 cm the tangents of A and B intersect at point P find the length of PA
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OB=10 CM
AB=16 CM
OP is perpendicular to AB
so, AB is bisected into 2 equal parts.
PA=PB [lengths of tangents to a circle from external point are equal.]
let PA=PB=x
also R is point of intersection from perpendicular P to AB.
in triangle ORB
by pythagoras theorem
OR = root [100-64]
OR=6 CM.
similarly we can show pythagoras theorem in triangle PBR.
sory i was getting late to go somewhere so can't solve the whole.
AB=16 CM
OP is perpendicular to AB
so, AB is bisected into 2 equal parts.
PA=PB [lengths of tangents to a circle from external point are equal.]
let PA=PB=x
also R is point of intersection from perpendicular P to AB.
in triangle ORB
by pythagoras theorem
OR = root [100-64]
OR=6 CM.
similarly we can show pythagoras theorem in triangle PBR.
sory i was getting late to go somewhere so can't solve the whole.
adyay:
When did the question mention that OP is perpendicular to AB..?
Answered by
1
AOBP forms kite as 0A=OB and PA=PB
SO OP is perpendicular to AB
Step-by-step explanation:
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