Question

In figure , ab is a tangent at c and cd is a chord of circle of a with centre o.prove that parpendiculerbcd =parpendiculer ced

Answer 1

Explanation:

BAP=75

∘

∠OAP=90

∘

∴∠OAB=90

∘

−75

∘

=15

∘

So, ∠AOB=180

∘

−2(15

∘

)=150

∘

∴Exterior∠AOB=360

∘

−150

∘

=210

∘

So, ∠ACB=

2

1

(210

∘

)=105

∘

[Angle subtended by an arc at the centre is double than the angle subtended by it at the remaining part of the circle]