Question

In figure AB is the diameter of a circle with center
0 and AT is a tangent,if angle AOQ = 58° . Find angle ATQ​

Answer 1

Angle ABQ=12 angle AOQ

=1/2'58

=29

Angle A =90(AT is a tangent) angle BAT+angle ABT +angle ATQ=180(angle sum

property of triangle.) 90+29+angle ATQ=180 angle ATQ=180-119 angle ATQ=61

Answer 2

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