In figure AB parallel to CD and a transversal PQ cuts them at L and M respectively. If, <QMD = 100, Find <LMD and <MLA
Answers
Step-by-step explanation:
Given that
, AB ∥ CD and ∠QMD = 100°
We know that, from the figure ∠QMD + ∠QMC = 180° is a linear pair
, ∠QMC = 180° – ∠QMD ∠QMC = 180° – 100°
∠QMC = 80°
Corresponding angles are ∠DMQ = ∠BLM = 100° ∠CMQ = ∠ALM = 80°
Vertically Opposite angles are ∠DMQ = ∠CML = 100° ∠BLM = ∠PLA = 100° ∠CMQ = ∠DML = 80° ∠ALM = ∠PLB = 80°
Step-by-step explanation:
In figure, AB || CD and a t...
Maths
In figure, AB∣∣CD and a transversal PQ cuts them at L and M respectively. If ∠QMD=100
o
, find all other angles.
1677543
Medium
Answer
Open in answr app
As per diagram AB∣∣CD and PQ is transversal
∠DMQ=100
o
[ Given]
∠DMQ=∠CML=100
o
[ Vertically opposite angles]
∠CML=∠ALP=100
o
[ Corresponding angles]
∠ALP=∠MLB=100
o
[ Vertically opposite angles]
∠CMQ=180−100=80
o
[sum of angle on a straight line is 180^o$$]
∠CMQ=∠LMD=80
o
[ Vertically opposite angles]
∠LMD=∠PLB=80
o
[ Corresponding angles]
∠PLB=∠ALM=80
o
[ Vertically opposite angles]
∴ ∠DMQ=∠CML=∠ALP=∠MLB=100
o
and ∠CMQ=∠LMD=∠ALM=∠PLB=80
o