Question

in figure ab parallel to CD the value of x is 35 degrees 40 degree 60 degree 75 degree​

Answer 1

Answer:

∵AB∥CD and BD is transversal.

∴x=40°(Alternate angles)

Now in △ABD

75°+y+x=180°(Sum of interior angles of a triangle)

⇒y=180°−75°−40°=180°−115°=65°

Now in △BCD

40°+(y−30°)+z=180°(Sum of interior angles of a triangle)

∴z=180°−40°−35°=180°−75°=105°