Math, asked by sanjay36571, 5 months ago

In figure, ∆ ABC, C is an acute and AD  BC. Prove that AB2 = BC2 + CA2 – 2 BC. DC.

Answers

Answered by 64004924
0

Answer:

It’s your work

Step-by-step explanation:

Solve it yourself

Answered by arpitmishrakash
0

Step-by-step explanation:

In △ABC,∠ABD=90°

By pathagores theorem

AB

2

=AD

2

+BD

2

In △ADC,∠ADC=90°

AC

2

=AD

2

+DC

2

AC

2

=AD

2

+(BC−BD)

2

AC

2

=AD

2

+BC

2

+BD

2

−BC×BD

AC

2

=(AD

2

+BD

2

)+BC

2

−BC×BD

AC

2

=AB

2

+BC

2

−BC×BD

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