In figure, ∆ ABC, C is an acute and AD BC. Prove that AB2 = BC2 + CA2 – 2 BC. DC.
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0
Answer:
It’s your work
Step-by-step explanation:
Solve it yourself
Answered by
0
Step-by-step explanation:
In △ABC,∠ABD=90°
By pathagores theorem
AB
2
=AD
2
+BD
2
In △ADC,∠ADC=90°
AC
2
=AD
2
+DC
2
AC
2
=AD
2
+(BC−BD)
2
AC
2
=AD
2
+BC
2
+BD
2
−BC×BD
AC
2
=(AD
2
+BD
2
)+BC
2
−BC×BD
AC
2
=AB
2
+BC
2
−BC×BD
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