Question

In figure, ΔABC has sides AB = 7.5 cm, AC = 6.5 cm and BC = 7 cm. On base BC a parallelogram DBCE of same area as that of ΔABC is constructed. Find the height OF of the parallelogram.​

Answer 1

Step-by-step explanation:

1 . First,find the area of the triangle ABC has sides

AB=7.5cm, AC=6.5cm, BC=7cm..by using the

heron's formula√s(s-a)(s-b)(s-c) where ABC are

the sides of the triangle

2 . √10.5(10.5-6.5) (10.5-7.5) (10.5-7)

3 . √10.5(4) (3) (3.5)

4 . 2√10.5×3×3.5

5 . 2√110.25

6 . 21

Therefore,21 is the area of triangle and the parallelogram...

Height of the parallelogram is ?

Area of parallelogram is b×h

7 . 7×h=21

8 . h= 3 cm

Therefore height of parallelogram is 3cm