In figure,ABC is an equilateral triangle BDC is an isosceles right triangle,right angled at D angle ABD equal to___
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Answer:
105°
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The answer is 105°
GIVEN
- ABC is an equilateral triangle
- BDC is an isosceles triangle
- ∠BDC = 90°
TO FIND
∠ABD
SOLUTION
We can simply solve the above problem as follows;
It is given
ΔABC is an equilateral triangle.
We know that,
∠ABD = ∠ABC + ∠DBC
Now,
All sides of an equilateral traingle are equal to one another,
Therefore,
AB = BC =CA
And,
All angles of an equilateral triangle are equal to 60°
Therefore,
∠ABC = 60° (Equation 1)
In ΔBDC
BD = DC (GIVEN)
∠BDC = 90° (GIVEN)
∠DBC = ∠DCB (Equal angles of equal sides)
Therefore,
∠BDC + ∠DBC + ∠DCB = 180° (Sum of interior angle of triangle is 180°)
90° + 2∠DBC = 180°
2∠DBC = 90
∠DBC = 90/2 = 45° (EQUATION 2)
Now,
(Equation 1) + (Equation 2)
∠ABD = 45 + 60 = 105°
Hence, The answer is 105°
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