Question

In figure abc is an equilateral triangle with side of length a find the length of its altitude ad​y

Answer 1

Answer:

√3/4 a^2 is the altitudes of the equilateral

Step-by-step explanation:

√3/4 a^2 is the altitudes of the equilateral triangle

Answer 2

The altitude of equilateral triangle=$\frac{\sqrt 3}{2} a$

Step-by-step explanation:

ABC is an equilateral triangle

Side of length of equilateral triangle=a

We know that

Equilateral triangle is that triangle in which three sides of triangle are equal.

We know that

Area of equilateral triangle ,$A=\frac{\sqrt 3}{4}a^2$

Where a= Length of side of equilateral triangle

Again , area of triangle =$\frac{1}{2}\times b\times h$

Where b=Base of triangle

h=Height of triangle

Using the formula then we get

$\frac{\sqrt 3}{4}a^2=\frac{1}{2}ah$

$h=\frac{\sqrt 3\times 2a}{4}=\frac{\sqrt 3}{2} a$

Hence, the altitude of equilateral triangle=$\frac{\sqrt 3}{2} a$

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https://brainly.in/question/2533041:Answered by Manuragkumar