In figure, ABC is an isosceles triangle in which AB=AC. Side BA is produced to D such that AD=AB. show that angle BCD is a right angle
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Figure:-
Given:-
- ABC is an isosceles triangle in which AB=AC. Side BA is produced to D such that AD=AB.
To prove:-
- <BCD is a right angle
Solutions:-
In ∆ACB,
AB = AC ⠀⠀⠀⠀⠀⠀⠀(Given)
<ACB = <ABC ⠀⠀(Angle opposite to equal side of triangle are also equal)
In ∆ACD,
AC = AD
<ADC = <ACD ⠀⠀(Angle opposite to equal side of a triangle are also equal)
In ∆BCD,
<ABC + <BCD + <ADC = 180° ⠀(Angle sum property of a triangle)
<ACB + <ACB + <ACD + <ACD = 180°
2 (<BCD) = 180°
<BCD = 180°/2
<BCD = 90°
Additional Information:-
- Straight line = Angle which measures 180°.
- Supplementary Angle = The two angle are supplementary, if there sum are 90°.
- Complementary Angle = The two angle are complementary, if these sum are 90°.
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