In figure ABC is an isosceles triangle with ab is equal to BC and angle abc is equal to 50 degree find the angle B and angle BEC
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Answer:
△ABC is an isosceles triangle.
∴∠B=∠C=50
o
∠BAC=180−50−50=80
o
∠BAC=∠BDC=80
o
(angles on circle by the same chord on the same side)
∠BEC is supplementary angle of ∠BAC
∴∠BEC=180−∠BAC
=180−80=100
o
@ananya
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