Question

In Figure ABCD, find the area of the shaded region.

Answer 1

□ Question => In figure ABCD , find the area of shaded region ?


□ Solution => Here , the given figure ABCD is a square , whose each sides is 20 cm.


□ We have to find :-


□ Area of shaded region = Area of the square - Area of the triangles i.e. ar[ EBF + EAF + CDE ]

Now ,


Area of the square = [ side ]^2

=> [ 20 ]^2

=> [ 20 ] * [ 20 ] = 400 cm^2


■ Hence , the area of square will be 400 cm^2


And ,


side [ DC = CB = AB = DA ] = 20 cm.

side [ AF = FB ] = 10 cm.

Then , side will be AE = AD - DE

AE = 20 - 8 = 12


■ Hence , the side AE = 12 cm.


□ Since two sides of a right triangle are perpendicular then one of the perpendicular side will be height and other will be base of a triangle.


Then , area of the will be ,


$\textbf{Area = 1 / 2 ( b * h )}$

According to the question ;

=> 400 - [ 1 / 2 * 10 × 20 ] + [ 1 / 2 * 10 × 12 ] + [ 1 / 2 * 8 × 20 ]

=> 400 - [ 100 ] + [ 60 ] + [ 80 ]

=> 400 - 240

=> 160 cm^2


■ Hence , the area of shaded region is 160 cm^2.




||||||| $\textbf{Thanks}$ |||||||

|||||| $\textbf{be brainly}$ ||||||| ☺

Answer 2

Hey friend

Your answer is given below :-

Area of shaded region =

Area of square = 2O × 2O = 44O

Area of three triangle = {1/2×2O × 2O} + {1/2×8×2O} × {1/2×8×2O}

= 24O

Area of shaded region = 44O - 24O

= 16O Answer

hope it helps you