Question

In figure ABCD find the area of the shaded region

Answer 1

Given, length of base, AB = 40 cm

Altitude of the triangle = 40 cm

Side of square = 40 cm

So, Area of shaded portion

= Area of square - Area of triangle

= 40^2 - 1/2 × 40 × 40

= 1600 - 20 × 40

= 1600 - 800 = 800 cm^2

Answer 2

$\huge\bf\mathscr\purple{Your\: Answer}$

800 ${cm}^{2}$

step-by-step explanation:

Given,

In square ABCD, a triangle lies inside ithaving base of ∆ on its one of the side AB.

therefore,

side length of Square = base length of triangle = 40 cm

also,

from the figure,

side length of Square = height of triangle = 40 cm

Now,

the are of Square = side × side

= ${(40)}^{2}$${cm}^{2}$

= 1600 ${cm}^{2}$

now,

the area of triangle = (base × height)/2

= 40 × 40/2 ${cm}^{2}$

= 800 ${cm}^{2}$

Now,

the area of shaded region

= area of ( square - triangle )

= (1600 - 800) ${cm}^{2}$

= 800 ${cm}^{2}$