Question

In Figure ABCD , find the area of the shaded region.

Answer 1

area of the square =20×20
=400sqcm

area of triangle EDC=1/2×20×8
=80sqcm

area of triangle EAF=1/2×12×10
=60sqcm

area of triangle FBC=1/2×10×20
=100sqcm

area of shaded part =area of square - area of unshaded part
=400-(80+60+100)
=400-240
=160sqcm

Answer 2

Answer:

Step-by-step explanation:

Area of square = 2O × 2O = 44O

Area of three triangle = {1/2×2O × 2O} + {1/2×8×2O} × {1/2×8×2O}

= 24O

Area of shaded region = 44O - 24O

= 16O Answer

hope it helps you