In figure ABCD is a cyclic quadrilateral such that angle BAD = 63°. Find the value of x in angle C 10x+7
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7
<BAD+<C=180`
63+10X+7=180`
70+10X=180`
10X=180-70
10X=110
X=110/10
X=11
63+10X+7=180`
70+10X=180`
10X=180-70
10X=110
X=110/10
X=11
Answered by
8
In a cyclic quadrilateral, the opposite angles' sum is 180 degrees
Here,
Angle BAD=63 degrees
Angle C=10x+7 degrees
A.T.Q.=>
=>63+10x+7=180
=>x=11 degrees
Now,
Angle C=10x+7
=>(10*11)+7
=>117 degrees
Here,
Angle BAD=63 degrees
Angle C=10x+7 degrees
A.T.Q.=>
=>63+10x+7=180
=>x=11 degrees
Now,
Angle C=10x+7
=>(10*11)+7
=>117 degrees
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