Question

In Figure ABCD is a parallelogram and E is the  mid-point of side BC. If DE and AB when  produced meet at F, then AF÷AB













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Answer 1

Answer:

Consider △ DEC and △ FEB

From the figure we know that ∠ DEC and ∠ FEB are vertically opposite angles

∠ DEC = ∠ FEB

∠ DCE and ∠ FBE are alternate angles

∠ DCE = ∠ FBE

It is given that CE = EB

By AAS congruence criterion

△ DEC ≅ △ FEB DC = FB (c. p. c. t)

From the figure AF = AB + BF

We know that BF = DC and AB = DC

So we get AF = AB + DC AF = AB + AB

By addition AF = 2AB

Therefore, it is proved that AF = 2AB

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Answer 2

Answer:

answer for the given problem is given