in figure ABCD is a parallelogram AP and cq are perpendiculars from the vertices a and c on diagonal BD respectively if a p upon cq = k find the value of k
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Since ABCD is a parallelogram. Therefore, DC∥AB.
Now DC∥AB and transversal BD intersects them at B and D.
Therefore, ∠ABD=∠BDC ∣ Alternate interior angles
in △APB and △CQD, we have
∠ABP=∠QDC ....(alternate interior angles of parallelogram ABCD and DC∥AB)
∠APB=∠CQD ....[each angle 90∘]
and AB=CD ∣ Opposite. sides of a || gm
Therefore, by AAS criterion of congruence
△APB≅△CQD
(ii) Since △APB≅△CQD
Therefore, AP=CQ ∣ Since corresponding parts of congruent triangles are equal
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