Question

in figure , ABCD is a parallelogram in BAC = 40° , DAC=30°.
, COD = 70° . find ABC and BCD​

Answer 1

∠AOB=∠COD=105

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(Vertically Opposite Angles)

In triangle AOB,

∠BAO+∠AOB+∠OBA=180

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30

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+105

∘

+∠OBA=180

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∠OBA=45

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AB and CD are parallel

∴∠OBA=∠CDO=45

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(Alternate Interior angles)

Answer 2

Correct answer:-

➙ In the figure, ABCD is a parallelogram in BAC = 40°, DAC = 30°, COD = 70°. Find ABC and BCD.

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