Question

In figure, ABCD is a parallelogram in which ∠A =60°. If the bisectors of ∠A and ∠B meet at P, prove that AD=DP, PC=BC and DC=2AD.
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Answer 1

Answer:

If the Bisectors of ∠A and ∠B Meet at P, Prove that Ad = Dp, Pc = Bc and Dc = 2ad. - Mathematics. In Fig., below, ABCD is a parallelogram in which ∠A = 60°. If the bisectors of ∠A and ∠B meet at P, prove that AD = DP, PC = BC and DC = 2AD.