in figure ABCD is a quadrant of a circle of radius 14 cm with ac as diameter a semicircle is drawn find the area of the shaded region
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area of shaded region=area(∆ABC)+area(CQA semicircle)-area (quadrant ABCP)=(1/2×14×14)+(1/2Π×7×7)-1/4Π×14×14
=98+77-15421Sq.cm
=98+77-15421Sq.cm
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