Question

In figure, ABCD is a rhombus in which angle ABD = 40°. Find

i. angle BAC

ii. angle BCD

iii. angle ADC

[ hint - angle BOA 90°( diagonal bisects at 90°)]

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Answer 1

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ABD=40°

Hint: BOA=90°..........( diagonal bisects at 90°)

We get,

=>AOB+OAB+ABO=180°

=>90°+OAB+40°=180°

=>AngleOAB=AngleBAC=50°

=>angleBDC = angleABD

=>BDC=40°

=>angleBAC=angleACD

=>ACD=50°