in figure ABCD is a square. if angle PQR=90 and PB=QC=DR, prove that angle QPR=45.
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Since PBCR becomes rectangle
∴ PB=RC=x
⇒AP=x
If QC=RC=x ∴∠CRQ=∠RCQ=
Since ∠PRC=
∴∠PRQ=
and sum of angles a triangle is
∴∠PQR= and ∠PRQ=
∴∠QPR=-(+)=
∴ PB=RC=x
⇒AP=x
If QC=RC=x ∴∠CRQ=∠RCQ=
Since ∠PRC=
∴∠PRQ=
and sum of angles a triangle is
∴∠PQR= and ∠PRQ=
∴∠QPR=-(+)=
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