In figure abcd is cyclic quadrilateral in which ac and bd are diagonals. If angle dbc=55 and angle bac=45. Find angle bcd.
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Step-by-step explanation:
∠DAC = ∠DBC = 55°
∠BAD= ∠DAC + ∠BAC
100°= 55°+45°
Now in the cyclic quadrilateral ABCD
∠BAD +∠BCD = 180°
100°+∠BCD =180°
∠BCD = 180° - 100°
∠BCD = 80°
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