Question

In figure ABCD is rectangle find the value of x and y.

Answer 1

CB=AD {opposite side of rectangle}

x-y=14------------(equation 1)



CD=AD{Opposite side of a rectangle}


x+y=30-----------(equation 2)


Now adding both the equation positive and negative y will be cancelled and we will get

2x=44
x=44/2=>22



Putting x in equation 1

x-y=14
22-y=14
-y=14-22
-y=-8
y=8

Answer 2

The value of x is 22 and y is 18

Step-by-step explanation:

Given ABCD is a rectangle.

AB = 30 cm, BC = x - y, CD = x + y, DA = 14 cm

In rectangle, opposite sides are equal.

⇒ CD = AB

x + y = 30

y = 30 - x ---------- (1)

In rectangle, opposite sides are equal.

⇒ BC = AD

x - y = 14

x - (30 - x) = 14 (using (1))

x - 30 + x = 14

2x = 14 + 30

2x = 44

x = 22

Substitute x = 22 in (1)

y = 30 - 22

y = 8

The value of x is 22 and y is 18.

To learn more...

1. Abcd is rectangle find the value of x and y ad=14cm ab=30cm cd=x+y bc=x-y

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2. In the fig1 ABCD is a rectangle . find the value of x and y AD =14cm AB=30cm DC=X+Y BC=X-Y

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