Question

In figure ABCD is rectangle of dimension 21cm *14cm semicircle is drawn with BC as diameter. Find area and perimeter of the given figure

Answer 1

Hope this might help you

Answer 2

Answer:

ABOUT THE FIGURE:

GIVEN THAT THE SEMI-CIRCLE IS DRAW WITH DIAMETER BC.

SINCE ITS GIVEN TO FIND THE SHADED REGION, THE SEMICIRCLE WILL BE INSIDE THE RECTANGLE.

METHOD TO SOLVE:

DIMENSIONS GIVEN=21 CM * 14 CM

==AREA OF THE RECTANGLE= B*H

21*14= 294 CM

TOTAL AREA OF THE RECTANGLE= 294 CM

==AREA OF THE SEMI-CIRCLE=1/2 PI R^2

RADIUS=DIMENSION ON THE SIDE BC

BC=14

RADIUS=HALF OF 14

RADIUS=7

1/2*22/7*7*7

77 CM

AREA OF THE SHADED REGION= AREA OF RECTANGLE-AREA OF THE SEMI-CIRCLE

294-77

=217 CM^2

THEREFORE, AREA OF THE SHADED REGION= 217 CM^2

PERIMETER=

PERIMETER OF RECTANGLE=2a+2b

2*21+2*14

42+28

=70

PERIMETER OF SEMI-CIRCLE= PI R

22/7*7

=22

PERIMETER OF THE FIGURE= PERIMETER OF RECTANGLE-PERIMETER OF SEMI-CIRCLE

70-22

=48CM

PERIMETER OF THE FIGURE=48 CM

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