Question

in figure ABCDE find angle 1+angle 2+ angle3+angle4+angle5 .please say the method

Answer 1

here is ur answer for which ur waiting for..

Answer 2

Answer:

$\angle 1+\angle 2+\angle 3+\angle 4+\angle 5=540^{\circ}$

Step-by-step explanation:

ABCDE is a pentagon.

We have to find the value of $\angle 1+\angle 2+\angle 3+\angle 4+\angle 5$.

In the given figure ∠1, ∠2, ∠3, ∠4, and ∠5 are interior angles of a pentagon.

Sum of interior angles = ∠1 + ∠2 + ∠3 + ∠4 + ∠5

Sum of interior angles of a polygon is

$Sum=(n-2)\times 180^{\circ}$

where, n is the number of vertices.

In the figure ABCDE, the number of vertices is 5.

Substitute n=5 in the above formula.

$Sum=(5-2)\times 180^{\circ}$

$Sum=3\times 180^{\circ}$

$Sum=540^{\circ}$

Therefore, the value of $\angle 1+\angle 2+\angle 3+\angle 4+\angle 5$ is 540°.