Question

in figure ABCDE find angle 1+angle 2+ angle3+angle4+angle5

Answer 1

the total angle in the pentagon is 540.

since any measure of angle is not given the measure of each angle would be 108

so,
∠ 1 = 108
∠2 = 108
∠3 = 108
∠4 = 108
∠5 = 108

∠1 +∠2 +∠3+∠4+∠5 =540

hope it helps.......

Answer 2

Answer:

540°

Step-by-step explanation:

ABCDE is a pentagon.

We need to find the value of $\angle 1+\angle 2+\angle 3+\angle 4+\angle 5$.

From the given figure it is clear that ∠1, ∠2, ∠3, ∠4, and ∠5 are interior angles of a pentagon.

Sum of interior angles = ∠1 + ∠2 + ∠3 + ∠4 + ∠5

Sum of interior angles of a polygon is

$Sum=(n-2)\times 180^{\circ}$

where, n is the number of vertices.

In the pentagon we have 5 vertices.

Substitute n=5 in the above formula.

$Sum=(5-2)\times 180^{\circ}$

$Sum=3\times 180^{\circ}$

$Sum=540^{\circ}$

Therefore, the value of $\angle 1+\angle 2+\angle 3+\angle 4+\angle 5$ is 540°.