Question

in figure ABCDE,find angle 1+angle2+ angle 3+ angle 4+ angle 5​

Answer 1

✧$\huge \mathcal \red {\underline{\underline{A}}}$ $\huge \mathcal \green {\underline{\underline{N}}}$ $\huge \mathcal \pink {\underline{\underline{S}}}$ $\huge \mathcal \blue {\underline{\underline{W}}}$ $\huge \mathcal \orange {\underline{\underline {E}}}$ $\huge \mathcal \purple {\underline{\underline{R}}}$✧

❥︎ Given :

A pentagon

❥︎ To find :

$\angle 1, \angle 2, \angle 3, \angle 4, \angle 5$

❥︎ Solution :

We know that,

All the interior angles of a regular pentagon is equal.

And,

$\textsf {Sum of interior angles of pentagon = 540°}$

Let all the angles be x.

Then,

→ $\angle 1 + \angle 2 + \angle 3 + \angle 4 + \angle 5 = 540°$

→ $\angle x + \angle x + \angle x + \angle x + \angle x = 540°$

→ $5x = 540°$

→ $x = \frac {540°}{5}$

→ $x = 108°$

$\implies$ Hence, the measure of $\angle 1, \angle 2, \angle 3, \angle 4, \angle 5$ is $\: 108°$.

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