In figure, AC= AE, AB=AD and angleBAD= angleEAC. Show that BC= DE.
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It is given that ∠BAD=∠EAC
∠BAD+∠DAC=∠EAC+∠DAC [add ∠DAC on both sides]
∴∠BAC=∠DAE
In △BAC and △DAE
AB=AD (Given)
∠BAC=∠DAE (Proved above)
AC=AE (Given)
∴△BAC≅△DAE (By SAS congruence rule)
∴BC=DE (By CPCT)
hope it helps
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