Math, asked by jeevan5001419, 3 months ago

In figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE.​

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Answered by prachi4042
15

Answer:

It is given that ∠BAD=∠EAC

∠BAD+∠DAC=∠EAC+∠DAC [add ∠DAC on both sides]

∴∠BAC=∠DAE

In △BAC and △DAE

AB=AD (Given)

∠BAC=∠DAE (Proved above)

AC=AE (Given)

∴△BAC≅△DAE (By SAS congruence rule)

∴BC=DE (By CPCT)

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Answered by Anonymous
3

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