Question

in figure, AC=BC, ANGLE DCA=ECB AND ANGLE DBC=EAC

experts plz answer plz someone plz

Answer 1

$\huge \underline\bold {Answer :-} \:$

✔️GIVEN :-

AC = BC

angleDCA = angleECB

angleDBC = angleEAC

✔️TO PROVE :-

i) ∆ DBC congruent to ∆ EAC

ii) DC = EC

iii) BD = AE

✔️ PROOF :-

In ∆ DBC and ∆ EAC,

DBC = EAC ...(given)-–––––––––(i)

BC = AC ....(given) –––––––––––(ii)

angle ECB+DCE = angle DCA+DCE ...(angle DCE is added to equal angles)

=> angle DCB = angle ECA –––––(iii)

from (i),(ii) and (iii)

∆ DBC congruent to ∆ EAC–(PROVED)

DC = EC ....(c.p.c.t.) –––––––(PROVED)

BD = AE ....(c.p.c.t.) –––––––(PROVED)

●▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬●

hope it will help you ✌️✌️

Answer 2

Hi friend..
See the attached files...


I hope it will help you mate
#yahyaahmad#
☺️✌️