Question

in figure ad=4cm bd=3cm and cb=12cm then cot theta =? Qn5​

Answer 1

cotQ = cosQ/sinQ

sinQ=p/h

cosQ = b/h

(AB)²=BD²+AD²

AB²=4² +3²

AB=√16+9

AB=√25

AB=5

.AC²=AB²+ BC²

AC²=5²+12²

AC²=25+144

AC²=169

AC=√169

=13

.cosQ=12/13

sinQ=5/13

cotQ=12/5

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Answer 2

Answer:

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