in figure AD=5.6 and AB=8.4cm AE=3.8cm and AC=5.7cm.To show taht DE is parallel to BC
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Answer:We have,
AD=5.6cm, DB=(AB-AD)=(8.4-5.6)CM=2.8CM
AE=3.8cm, EC=(AC-AE)=(5.7-3.8)CM=1.9CM
∴
A
E
E
C
−
3.8
1.9
−
2
1
a
n
d
A
D
D
B
−
5.6
2.8
−
2
1
Thus,
A
D
D
B
−
A
E
E
C
∴
DE divides AB and AC proportionally.
Hence, DE||BC
Step-by-step explanation:
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