Question

in figure AD =BC 7.5cm and CD =1.5cm then find the measure of AC + BD​

Answer 1

Given:

AD =BC = 7.5cm and CD =1.5cm

To Find:

AC+BD = ?

Solution:

Here,

$AD= AB+BC+CD\\7.5=AB+7.5+1.5\\AB+1.5=0\\AB=(-1.5)$

Therefore,

$AC+BD=(AB+BC)+(BC+CD)\\=AB+2BC+CD\\= -1.5 + 2(7.5)+1.5\\=15.0$

Hence, $AC+BD = 15$

Answer 2

Given:

AD =BC = 7.5cm and CD =1.5cm

To Find:

AC+BD = ?

Solution:

Here,

$\begin{gathered}AD= AB+BC+CD\\7.5=AB+7.5+1.5\\AB+1.5=0\\AB=(-1.5)\end{gathered}$

Therefore,

$\begin{gathered}AC+BD=(AB+BC)+(BC+CD)\\=AB+2BC+CD\\= -1.5 + 2(7.5)+1.5\\=15.0\\\end{gathered}$

Hence, AC+BD = 15AC+BD=15