Math, asked by kareena42, 10 months ago

in figure, AD is a median of a triangle ABC and AM perpendicular to BC. Prove that: AC^2 = AD^2 +BC.DM + (BC/2)^2

HURRY UP GUYS!!! IT IS A BIT URGENT......

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Anonymous: Hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

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Answered by Anonymous

7

Refer the attached picture.

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kareena42: a bit difficult one!.... but i got it now thank u so much

Answered by anu24239

14

HII...........¶

THERE IS YOUR ANOTHER ANSWER...

∆ ANUBHAV VASHISHTHA ∆

HOPE IT'S HELP YOU.....

^_^

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anu24239: hey kareena do you read all my answer i answered last night

kareena42: yes

anu24239: ok

anu24239: it help u or not

anu24239: chemistry'answers

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