In figure,adjoining LA= (2x+ 5°,LB= (x + 2)° and LCD = 109° then the value of x the is
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\begin{gathered} \angle ACD = \angle C = 109° \\ \\ Sum \: of \: all \: angle \: of \: triangle = {180}^{\circ} \\ \\ 2x +5 + x +2 + 109 = 180 \\ \\ 3x + 7 = 71 \\ \\ 3x = 64 \\ \\ x = {21.5}^{\circ} \\ \end{gathered}
∠ACD=∠C=109°
Sumofallangleoftriangle=180
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2x+5+x+2+109=180
3x+7=71
3x=64
x=21.5
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