Question

In figure, AM and CN are perpendiculars to the diagonal BD of a parallelogram ABCD. Prove that AM = CN.​

Answer 1

Step-by-step explanation:

In triangle PAQ & BQC,

I. DA=BC

ii. <ADB=<QBC (alternate angle)

iii. <DPQ=<CQB (GIVEN)

Therefore, by AAS,

triangle PDA congruent to triangle BCQ

Therefore by CPCT,

AP=CQ