Question

In figure and show that AD < BC

Answer 1

Given: ∠B < ∠A and, ∠C < ∠D

Now,

AO < BO (i) (Side opposite to the smaller angle is smaller)

OD < OC (ii) (Side opposite to the smaller angle is smaller)

Adding (i) and (ii), we get

AO + OD < BO + OC

AD < BC

Hence Proved.

Please mark it as a brain list answer

Answer 2

where is the figure?please attatch the figure with question