Question

in figure angle ACB is an exterior angle of triangle abc angle A is 60 degree angle b is 40 degree then find the angle ACP​

Answer 1

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

Hence, In this case ∠A and ∠B

So,

∠A+∠B=140 ∘

as ∠A=∠B

or,2∠A=140 ∘

∠A=∠B=70 ∘

Answer 2

Answer:

Angle A+ angle B=angle ACD( exterior angle property)

=>Angle A+30°=120°

=>Angle A=120°-30°

=>Angle A=90°

Now,

Angle ACD+ Angle ACB=180°(linear pair)

=>120°+Angle ACB=180°

=>Angle ACB=180°-120°

=>Angle ACB=60°